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/* The C Programming Language my answer to exercise 2-3 Convert a hexadecimal string to an integer. */ #include <stdio.h> #include <stdlib.h> #include <string.h> #include <math.h> int htoi(char h[]); int main(int argc, char* argv[]) { char hex[] = "0xDEAD"; printf("%s in hex is equivalent to %d", hex, htoi(hex) ); return 0; } /* Accepts a string of hexadecimal characters and returns its equivalent integral value. */ int htoi(char h[]) { int dec, n, i; dec = n = 0; for (i = strlen(h)-1; i >= 0; --i, ++n) if (h[i] == '0') continue; else if (h[i] >= '0' && h[i] <= '9') dec += (h[i] - '0') * pow(16,n); else if(h[i] >= 'A' && h[i] <= 'F') dec += (h[i] - 'A' + 10) * pow(16,n); else if(i == 1 && h[i] == 'x' && h[i-1] == '0') return dec; else return 0; return dec; }
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