codepad
[
create a new paste
]
login
|
about
Language:
C
C++
D
Haskell
Lua
OCaml
PHP
Perl
Plain Text
Python
Ruby
Scheme
Tcl
#include <cstdio> #include <cmath> using std::printf; #define PRECISION 1e-4 //exp(x) = 1 + x + (x^2)/2!+(x^3)/3!....+(x^n)/n!+..... double _exp( const double x ){ double dVal, dTemp; int nStep = 1; for( dVal = 1.0, dTemp = 1.0; dTemp >= PRECISION ; ++nStep ){ dTemp *= x/nStep; dVal += dTemp; } return dVal; } int main(){ double x = 2.3; printf( "exp(%f) = %3.10f, prec = %3.10f\n", x, _exp( x ), _exp( x) - std::exp( x ) ); x = 8.5; printf( "exp(%f) = %3.10f, prec = %3.10f\n", x, _exp( x ), _exp( x) - std::exp( x ) ); return 0; }
Private
[
?
]
Run code
Submit