Language: C C++ D Haskell Lua OCaml PHP Perl Plain Text Python Ruby Scheme Tcl def ackermann(m, n): while m >= 4: if n == 0: n = 1 else: n = ackermann(m, n - 1) m = m - 1 if m == 3: return (1 << n + 3) - 3 elif m == 2: return (n << 1) + 3 elif m == 1: return n + 2 else: return n + 1 print ackermann(4,2) Private [?] Run code Submit