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/*! @file 9times_test.cpp @brief 9を掛けた数字の各桁を合計すると必ず9の倍数になる法則の確認. @par 著作権 Copyright(c)2012-2013 0xef All rights reserved. @author 0xef @date Ver 1.00 Written by 0xef @Last Change: 19-Jun-2013. */ typedef unsigned int u32; u32 sum_digits( u32 val ) { u32 ret=0; char buffer[64]={}; sprintf( buffer, "%u", val ); for( u32 i=0;i<strlen(buffer);++i ){ ret += (buffer[i]-'0'); } return ret; } bool isDiv9( u32 val ) { return ( val % 9 == 0 ); } int main() { //const u32 start = 1; //const u32 loop = 1000; const u32 start = 457121386; const u32 loop = 1000; for( u32 i=start;i<start+loop;++i ) { const u32 val = i * 9; const u32 s = sum_digits( val ); std::cout << i << " * 9 = " << val << " の各桁の合計は" << s << "で 9で割り切れ" << (isDiv9(val)?"る":"ない") << std::endl; } }
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