class Straddling 
def initialize( key_text, n1, n2, n3 )
   key_text = key_text+"ABCDEFGHIJKLMNOPQRSTUVWXYZ"
   key_text = key_text.upcase.split(//).uniq
   @key_text = key_text

class Straddling 
def initialize( key, n1, n2, n3 )
   key = key+"ABCDEFGHIJKLMNOPQRSTUVWXYZ"
   key = key.upcase.split(//).uniq
   @key = key;@n1 = n1;@n2 = n2;@n3 = n3

def julian (year, month, day)
a = (14-month)/12
y = year+4800-a
m = (12*a)-3+month
return day + (153*m+2)/5 + (365*y) + y/4 - y/100 + y/400 - 32045

#include <stdio.h>
#include <time.h>
int s(int i, int j, int a,int b){
  return (i == 0 || j == (b-1)) ? \
  (a*b) - (1 + i + j) : (i == (a-1) || j == 0) ?\

#include <stdio.h>
#include <time.h>
int s(int i, int j, int a,int b){
  return (i == 0 || j == (b-1)) ? \
  (a*b) - (1 + i + j) : (i == (a-1) || j == 0) ?\

#include <cstdlib>
#include <ctime>
#include <iostream>
using namespace std;

/* print list of numbers in spiral direction */
#include <iostream>
using namespace std;
int i=0,x=25,y=10,spiral[100][100];
char direction = 'r';

/*
numeric diamond algorithm..
not sure if this is the fastest algorithm
novatech - http://wan.pengganas.net
*/

#include <stdio.h>

int main() {
 int i,j,k,x,size = 100;
 x = sqrt(size);

/*
 * coded by novatech
 * http://wan.pengganas.net
 * print doreamon song (modified) malay version
 * lyrics is not 100% correct because i didn't remember it

/*
find what is the smallest number that is evenly divisible by all of the numbers from 1 to 20?.
using LCM formula refer to http://en.wikipedia.org/wiki/Least_common_multiple
*/
#include <iostream>

#include <stdio.h>
/* malaysia.c will print the map of
/* peninsular malaysia in ascii form
/* copyright novatech@pengganas.net
/* http://wan.pengganas.net - July 2009

#include <stdio.h>
#include <math.h>
#define PI 3.141592654
/*
long double factorial(int n)