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Link: http://codepad.org/3scFzIdo    [ raw code | output | fork ]

PHP, pasted on Jan 9:
	$employee_query = mysql_query("SELECT * FROM `accounts` WHERE NOT `name` = '$username' ORDER BY `last` ASC");
	$i = 0;
	echo '<div align="center"><div class="title">Edit Employee Accounts</div><br /></div>
		<form method="post" action="employee.php?page=edit_employees">
		<div align="center">';
		?>
		<select name="selected" class="my-select">
		<?php

	while($employee_data = mysql_fetch_array($employee_query)){
		$rNames = $employee_data['name'];
		$id = $employee_data['id'];
		$last = $employee_data['last'];
		$first = $employee_data['first'];
	$i++;
	?>
					<option value="<?php $id ?>"<?php if($i <= 1) { echo ' selected'; } ?>><?php echo $last . ', ' . $first; ?></option>
	<?php
	}
	?>
	</select>
	<?php
	echo '</div>
	<table align="center">
	<tr>
	 <td align="center" valign="center">Choose new account status:</td>
         		 <td><input type="radio" name="choice" checked value="user">User<br>
			     <input type="radio" name="choice" value="manager">Manager<br>
            		     <input type="radio" name="choice" value="admin">Administrator<br></td></tr>
	<tr><td align="center"><input type="submit" name="update_users" value="Submit" /></td></tr></table>';
	include('includes/update_users.php');
	echo '</form>';	
}


Output:
1
2

Parse error: syntax error, unexpected '}' on line 33


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