<?PHP
/*
* 新しい配列 $new
*/
$new = array(
'2019-01-02'=> array(
array(
'action'=>'banana',
'time'=>'01-02',
'targetID'=>'1',
'actorID'=>'17',
'subID'=>'77',
)
)
);
/*
* 現在の配列 $current
*/
$current = array(
'2019-01-02'=> array(
array(
'action'=>'orange',
'time'=>array('01-02','01-01'),
'targetID'=>'200',
'actorID'=>array('16','15'),
'subID'=>array('6','22'),
),
array(
'action'=>'apple',
'time'=>array('01-02','01-01'),
'targetID'=>'1',
'actorID'=>array('14','13'),
'subID'=>array('86','64'),
),
),
'2019-01-01'=> array(
array(
'action'=>'apple',
'time'=>array('01-01','01-01'),
'targetID'=>'1',
'actorID'=>array('4','3'),
'subID'=>array('1','33'),
),
),
);
foreach($new as $day => $contents) {
foreach($contents as $content) {
//【処理1】同じ年月日がなければ、年月日の配列を連結して終了
if(!isset($current[$day])) {
$current = array_merge($new, $current);
continue;
}
//【処理2】同じactionがなければ、年月日の配列を連結して終了
if($current[$day]['action'] !== $content['action']) {
$current = array_merge($new, $current);
continue;
}
//【処理3】同じ年月日で同じactionがあれば、年月日の配列の中の３つの配列を連結して、新しい20個だけをとっておく
for($i = 0; $i < count($current[$day]); $i++) {
$current[$day][$i]['time'] = array_slice(array_merge([$content['time']], $current[$day][$i]['time']), 0, 20);
$current[$day][$i]['actorID'] = array_slice(array_merge([$content['actorID']], $current[$day][$i]['actorID']), 0, 20);
$current[$day][$i]['subID'] = array_slice(array_merge([$content['subID']], $current[$day][$i]['subID']), 0, 20);
}
//新しいのを上に
$sortkey = array_map(function($ar) { return $ar[0];}, array_column($current[$day], 'time'));
array_multisort($sortkey, SORT_DESC,$current[$day]);
}
}
var_export($current);