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Link: http://codepad.org/5igM638W    [ raw code | output | fork ]

C, pasted on Sep 23:
#include <stdio.h>
#include <inttypes.h>



int aradius = 2;

int main()
{
    int i;
    int j;
    int amax = 10;
    int ax[10];
    int ay[10];
    int bx[10];
    int by[10];
    int cx[10];
    int cy[10];
    int cnt = 0;
    
    for(i=0; i<amax; i++)
    {
        ax[i] = 0;
        ay[i] = 0;
        bx[i] = 0;
        by[i] = 0;
        cx[i] = 0;
        cy[i] = 0;
    }
    ax[2] = 1;
    ay[3] = 1;
    bx[6] = 1;
    by[8] = 1;


    //a와 b에 1이 있는지 확인
    for(i=0; i<amax; i++)
    {
        for(j=0; j<amax; j++)
        {
            if((ax[i] == 1) && (ay[j] == 1) || (bx[i] == 1) && (by[j] == 1) )
            {
                printf("1");
cx[cnt] = i;
cy[cnt] = j;
cnt++;
            }
            else
            {
                printf("0");
            }
        }
        printf("\n");
    }
    printf("-----------------------\n");


    //확인된 a와 b 에 위치
    for(i=0; i<10; i++)
    {
        printf("cx:%d   cy:%d\n", cx[i], cy[i]);
    }

    //cx:2   cy:3
    //cx:6   cy:8
    printf("-----------------------\n");


    //b영역 안에. a영역이 있는지 확인
    int i2;
    int j2;
    int c2;
for(c2=0; c2<10; c2++)
{
    if((cx[c2] == 0) && (cy[c2] == 0))
    {
        break;
    }

    for(i2=-aradius+cx[c2]; i2<aradius+cx[c2]; i2++)
    {
        for(j2=-aradius+cy[c2]; j2<aradius+cy[c2]; j2++)
        {
            if(i2<0) continue;
            if(i2>=amax) continue;

            if(j2<0) continue;
            if(j2>=amax) continue;

            printf("[%d,%d]", i2, j2);
            if((ax[i2] == 1) && (ay[j2] == 1) || (bx[i2] == 1) && (by[j2] == 1) )
            {
                if((cx[i2] == ax[i2]) && (cy[j2] == ay[j2]))
                {
                    printf("A ");
                    continue;
                }
                else if((cx[i2] == bx[i2]) && (cy[j2] == by[j2]))
                {
                    printf("B ");
                    continue;
                }
                else
                {
                    printf("1 ");
                }

//                printf("%d,%d %d,%d %d,%d \n", ax[i2], ay[j2], bx[i2], by[j2], i2, j2);
            }
            else
            {
                printf("0 ");
            }
        }
        printf("\n");
    }
    printf("------------------\n");
}
    return 0;
}


Output:
0000000000
0000000000
0001000000
0000000000
0000000000
0000000000
0000000010
0000000000
0000000000
0000000000
-----------------------
cx:2   cy:3
cx:6   cy:8
cx:0   cy:0
cx:0   cy:0
cx:0   cy:0
cx:0   cy:0
cx:0   cy:0
cx:0   cy:0
cx:0   cy:0
cx:0   cy:0
-----------------------
[0,1]0 [0,2]0 [0,3]0 [0,4]0 
[1,1]0 [1,2]0 [1,3]0 [1,4]0 
[2,1]0 [2,2]0 [2,3]B [2,4]0 
[3,1]0 [3,2]0 [3,3]0 [3,4]0 
------------------
[4,6]0 [4,7]0 [4,8]0 [4,9]0 
[5,6]0 [5,7]0 [5,8]0 [5,9]0 
[6,6]0 [6,7]0 [6,8]A [6,9]0 
[7,6]0 [7,7]0 [7,8]0 [7,9]0 
------------------


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