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Link: http://codepad.org/DDaU9FJu    [ raw code | output | fork | 1 comment ]

Maxus - C++, pasted on Jan 16:
#include <iostream>
#include <vector>

int OrderingsNumber(int n) {
  std::vector<std::vector<int> > f(n+1, std::vector<int>(n+1));
  f[1][0] = 1;
  int factorial = 1;
  for (int i = 2; i <= n; i++) {
    f[i][0] = 1;
    factorial *= i;
    f[i][i-1] = factorial;
    for (int k = 1; k < n - 1; k++) {
      f[i][k] = (k + 1) * (f[i-1][k-1] + f[i-1][k]);
    }
  }
  int answer = 0;
  for (int i = 0; i < n; i++) {
    answer += f[n][i];
  }
  return answer;
}

int main() {
  std::cout << OrderingsNumber(3) << std::endl;
  return 0;
}


Output:
1
13


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Comments:
posted by M150128CS on Nov 12
the code has complexity n^2 can you give an order of n colution...
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