C,
pasted
on Aug 17:
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#include<stdio.h>
#include<conio.h>
double Power_n(double x, long n)
{
// n >= 0
double result = 1;
while(n--)
{
result = result * x;
}
return result;
}
double qPower_n(double x, long n)
{
// n >= 0
double result = 1;
while(n)
{
if(n % 2 == 1)
{
result = result * x;
}
x = x * x;
n = n / 2;
}
return result;
}
int main()
{
double x = 3;
long n = 2;
double z;
z = qPower_n(x, n);
printf("z = %f", z);
getch();
return 0;
}
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Output:
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Line 17: error: conio.h: No such file or directory
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Create a new paste based on this one
Comments:
posted by
Tuankhoilua
on May 5
#include <iostream>
using namespace std;
int Mu(int a, int b)
{
if(b == 1)
return a;
else
{
return Mu(a, b - 1)*a;
}
}
int main ()
{
// Tinh t(x,n)=x^n
int Tn = 0, x, n;
cout << "Nhap x ";
cin >> x;
cout << "Nhap n ";
cin >> n;
cout << "T(n) = " << Mu(x ,n) << endl;
system ("pause");
return 0;
}
reply
posted by
khanhtienfz
on Jun 24
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
int n;
do{
printf("\nNhap n = ");
scanf_s("%d", &n);
} while (n < 0 && printf("\nXin vui long nhap lai "));
int x;
printf("\nnhap vao x =");
scanf_s("%d", &x);
int i=1,s = 1;
while (i<= n)
{
s = s*x;
i++;
}
printf("s=%d", s);
//Hoặc có thể dung hàm pow trong thư viện math.h
//Hàm pow <=> lũy thừa
//Ví dụ x^n=pow(x,n)
printf("\n\n");
system("pause");
return 0;
}
reply
posted by
hochoi1368
on Dec 3
#include<iostream>
#include<conio.h>
#include<math.h>
using namespace std;
int main()
{
double x,n;
double T;
do{
cout << "nhap x: ";
cin >> x;
if(x==0){
cout << "moi ban nhap lai!\n";
}
}while(x==0);
cout << "nhap n:";
cin >> n;
T = pow(x,n);
cout <<x<< "^"<<n<< " = "<<T<<endl;
return 0;
}
reply
posted by
phamquanghoaz
on Aug 19
cho e hỏi là nếu n < 0 thì lũy thừa nó sẽ ra 1/ x^n mà sao e code miết không ra, có ai chỉ e với
reply
posted by
thongvien123
on Aug 2
#include<stdio.h>
#include<conio.h>
double Txn(int x, int n){
double T = 1;
double a = n;
if (n < 0)
{
a *= -1;
}
for (int i = 0; i < a; i++)
{
T *= x;
}
return T;
}
int main (){
double x;
printf("Enter x: ");
scanf("%lf", &x);
double n;
printf("Enter n: ");
scanf("%lf", &n);
double result = Txn(x, n);
double R = 1.0 / result;
if (n >= 0)
{
printf("\n=> T(%.3f^%.3f) = %.3f", x, n, result);
}else
{
printf("\n=> T(%.3f^%.3f) = %.3f", x, n, R);
}
getch();
return 0;
}
reply
posted by
vjpkerpoker
on Jan 3
#include <stdio.h>
int main()
{
int x, n;
printf("nhap x:");
scanf("%d", &x);
printf("nhap n:");
scanf("%d", &n);
int sum = 1;
int a = 1;
while (a <= n)
{
sum = sum * x;
a++;
}
printf("%d^%d=%d", x, n, sum);
}
reply
posted by
vjpkerpoker
on Jan 3
#include <stdio.h>
int main()
{
int x, n;
printf("nhap x:");
scanf("%d", &x);
printf("nhap n:");
scanf("%d", &n);
int sum = 1;
int a = 1;
while (a <= n)
{
sum = sum * x;
a++;
}
printf("%d^%d=%d", x, n, sum);
}
reply
posted by
B21DCVT339
on Aug 1
#include"stdio.h"
#include"math.h"
int main(){
double x,T;
scanf("%lf",&x);
int n;
scanf("%d",&n);
T=pow(x,n);
printf("%.2lf",T);
}
reply
posted by
B21DCVT339
on Aug 1
#include"stdio.h"
#include"math.h"
int main(){
double x,T;
scanf("%lf",&x);
int n;
scanf("%d",&n);
T=pow(x,n);
printf("%.2lf",T);
}
reply